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Answer: CH₄ CH₃OH CH₂O HCOOH CO₂ Explanation: In order to know the oxidation number of C in these compounds, we will use the rule that states that the sum of the oxidation numbers of the atoms is equal to the charge of the compound, in these cases, zero because these are neutral molecules. The reducing agent is CH3OH, whose C changes from -2 to +2. Questions; general chem. Deriving the oxidation number of carbon in this compound is easy. 1 decade ago. The first has an oxidation number:-3, the second has an oxidation number of +3. 0 2. Fluorine's oxidation number is -1. What is the oxidation number of what? Given that oxidation number is an empirical concept; the oxidation number of C in methanol is -II; in formaldehyde it is 0. Since there are four fluorine atoms, the total oxidation number for the fluorine portion of the molecule is -4. The first has an oxidation number:-3, the second has an oxidation number of +3. On the Pauling scale, we can quote the electronegativities of C … asked Oct 7, 2018 in Chemistry by Afreen ( 30.6k points) oxidation-reduction You have two different carbon atoms. CH2O. 0 2. Reduction is the gain of electrons or the decrease in oxidation number, so MnO4- is reduced. The oxidation number of a compound is zero. The oxidizing agent is MnO4-, with the oxidation number of Mn changing from +7 to +2. Source(s): myself. Since is in column of the periodic table, it will share electrons and use an oxidation state of . Oxidation number (also called oxidation state) is a measure of the degree of oxidation of an atom in a substance (see: Rules for assigning oxidation numbers). C will be ==> -2. H is +1 ==> +2. O is -2 ==> -2. C will be ==> 0. Carbon can have any oxidation number from -4 to +4. H is +1 ==> +4. The oxidation state of carbon in CH3OH is 4. Mn +7 O -2 4 - + C -2 H +1 3 O -2 H +1 → H +1 C +2 O -2 O -2 H +1 + Mn +2 2+ The C-C bond doesn't make additional number for oxidation number. CH3OH. Oxidation number/oxidation state is an empirical construct, It is formally the charge left on the central metal atom when all the bonds are broken, with the charge devolving to the most electronegative atom. Find the oxidation number of carbon in the following compounds : CH3OH, CH2O, HCOOH, C2H2 . Determine the oxidation number for the indicated element in each of the following compounds: (a) Co in LiCoO2, (b) Al in NaAlH4, (c) C in CH3OH (methanol), (d) N in GaN, (e) Cl in HClO2, (f) Cr in BaCrO4. To find the oxidation state of , set up an equation of each oxidation state found earlier and set it equal to . therefore O=-2. Oxidation is the loss of electrons or the increase in oxidation number, so CH3OH is oxidized. O is -2 ==> -2. 2)The oxidation number of (C) in CH3OH,CH2OH, HCOOH and C2H2 is respectively.a) -2,0, +2.-1 b)-2, 4, +2,-2c) -… Get the answers you need, now! Takker.

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